If grep -m NUM is unavailable, you can just pipe to head, e.g. Is this possible using a grep Update: /bin/sh FILEtext.txt STRING1 grep. Word1 Word2 - Word3 Word4 Word5 Word1 Word6 Word3 Word7 Word8 And in the search i search for 'Word1 Word3' I want it to still output these lines as the search case matches this line. Could probably do it with one sed thought that gets more messy. I want to expand on this where i have multiple details in the text file such as. If you want to search multiple patterns or strings in a particular file, use the grep functionality to sort within a file with the help of more than one input word in the command. Where the sed matches any line containing Job completed successfully and returns from that line to the end of the file and grep -m NUM shows only the first NUM matches of grep. In this article, we will show you how to use grep to search multiple strings and patterns at once in Linux. When it finds a pattern that matches in more than one file, it prints the name of the file. ![]() You can pipe it like so | sed -n -e '/Job completed successfully/,$p' | grep -m 1 "affected"Į.g $ printf "1 row affected.\nsomeline\nsomeline\nJob completed successfully\nsomeline\nsomeline\n2 row affected.\n3 row affected.\n" | sed -n -e '/Job completed successfully/,$p' | grep -m 1 "row affected" string1 < string2 < string3) you can do the following: egrep (string1string2string3) /some/file.txt sort. The grep command can search for a string in groups of files. ![]() Let's say you only want the first row after "Job completed successfully" that contains "row affected". This tutorial explains how to search for matches of certain. Assuming some input like $ printf "1 row affected.\nsomeline\nsomeline\nJob completed successfully\nsomeline\nsomeline\n2 row affected.\n3 row affected.\n" grep & grepl R Functions (3 Examples) Match One or Multiple Patterns in Character String.
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